ABC is an isosceles right angled triangle, right angled C .prove that AB²=2AC²
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Answered by
21
HEYA!!
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⬆⬆Refer to the Attachment for the figures ⬆⬆
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We have
AC = BC { triangle is isosceles}........................(1)
Also by Pythagoras theorem , we have
AB^2 = AC^2 + BC^2
AB^2 = 2 AC^2 { putting BC=AC from (1) }
Thus proved !!
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---------
==================---------------------------------------------------==============
⬆⬆Refer to the Attachment for the figures ⬆⬆
==================----------------------------------------------------==============
We have
AC = BC { triangle is isosceles}........................(1)
Also by Pythagoras theorem , we have
AB^2 = AC^2 + BC^2
AB^2 = 2 AC^2 { putting BC=AC from (1) }
Thus proved !!
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Answered by
23
DIAGRAM:
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⠀⠀⠀⠀⠀⠀ ⠀━━━━━━━━━━━━━━━━━━━━━━━━━━
⠀☯ Since ∆ABC is an Isosceles right triangle right - angled at C.
⠀⠀⠀
Therefore,
- AC = BC
⠀⠀⠀
☯ Now, Using Pythagoras Theorem
⠀⠀⠀
⠀⠀⠀⠀⠀⠀ ⠀━━━━━━━━━━━━━━━━━━━━━━━━━━
★ Isosceles Right triangle -
- In an isosceles right angled triangle, the equal sides make the right angle (90°). They have the ratio of equality 1:1.
★ Pythagoras Theorem -
- Pythagoras theorem states that "In a right-angled triangle, the square of the hypotenuse is equal to the sum of squares of the other two sides i.e base and perpendicular".
- The sides of this triangle have been named as Perpendicular, Base and Hypotenuse.
- Here, the hypotenuse is the longest side, as it is opposite to the angle 90°.
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