Question

ABC is an isosceles right Triangle atC. prove that AB square =2AC square​

Answer 1

Step-by-step explanation:

So, since C is your right angle, the opposite line, which is AB, is the hypotenuse.

So, by the pythagorean relation,

AB^2 = AC^2+ BC^2.

and it is also given that the triangle is isosceles. this means that 2 of the sides are equal in length. But since the hypotenuse is the longest side, it can't be equal to any other side, which means that AC = BC.

Therefore, AC^2 = AB^2.

so substituting AC^2 for BC^2 we get,

AB^2 = AC^2 + Ac^2

which implies that

AB^2= 2AC^2

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Answer 2

Hey buddy here is ur answer !!!!!

GIVEN: triangle ABC is an isosceles right Triangle at C.

TO PROVE THAT :

$AB^2 = 2AC^2$

PROOF :

triangle ABC is an isosceles

Such that ,

AC = BC

So in a triangle ABC ,

$AB^2 = BC^2 + AC^2$

(Pythagorus theorem)

(also we know that BC = AC)

so

$AB^2 = 2 AC^2$


hope u like the process !!


$BE BRAINLY$