Question

ABC is an isosceles triangle and B = 90°. then show that AC2=2AB2?​

Answer 1

Step-by-step explanation:

Given ∆ABC is an isosceles triangle

=> any two sides must be equal

so let AB=BC

and also given that angle at B =90

=> ∆ ABC is also a right angle triangle

so we can right that,

AC^2= AB^2+BC^2

AC^2= AB^2+AB^2 (since AB=BC)

AC^2=2AB^2