ABC is an isosceles triangle Angle C= 90°, prove that AB²=2AC²
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ABC is an isosceles traingle so AC= BC
C = 90°
BY PYTAGORUS THEOREM
AB2= AC2+BC2
AB2 = 2(AC )2
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C = 90°
BY PYTAGORUS THEOREM
AB2= AC2+BC2
AB2 = 2(AC )2
HOPE IT HELPS
PLEASE MARK IT AS BRAINLIEST
DON'T FORGET TO FOLLOW
Tasmiyak:
plz mark it as brainliest
Answered by
6
Hence,proved..that AB square is 2 times of AC square.
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