Question

ABC is an isosceles triangle b=90 then find 2sinACosA​

Answer 1

Ello user

So, the other two angle should be equal and will be 45° each.

So, 2sinACosA = sin90° = 1

Hope this helps

Answer 2

An isosceles triangle is a type of triangle that has any two sides of equal length. Two angles of an isosceles triangle, opposite to the same sides, are equal in measure. In geometry, a triangle is a three-sided polygon that is classified into three categories based on its sides, such as:

• Scalene triangle (all three sides are unequal)
• Isosceles triangle (only two sides are equal)
• Equilateral triangle (all three sides are equal)

An isosceles triangle is a triangle that has two sides equal. Also, two angles opposite two equal sides are equal. In other words, we can say that "an isosceles triangle is a triangle that has two congruent sides".

Suppose in triangle △ABC, if sides AB and AC are equal, then △ABC is an isosceles triangle where ∠ B = ∠ C. The theorem that describes an isosceles triangle is “if two sides of a triangle are congruent, then the angle opposite to it is also identical to them".

2sinA cosA. = sin2A

in isosceles∆ .

One angle is the right angle so the remaining two must be 45°

And two sides are equal ( i.e . base & perpendicular) = a

So the hypotenuse would be a√2 by Pythagoras theorem.

In ∆ABC

Ang B = 90°

Ang A = Ang C = 45°

so Sin 2A = Sin 2× 45°

= Sin 90°

= 1

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