Question

ΔABC is an isosceles triangle. Find the value of x in the given figure

ANSWER AS FAST AS POSSIBLE PLEASE!

Answer 1

Step-by-step explanation:

Given, △ABC is an Isosceles triangle.

We know, by isosceles triangle property, angles opposite to equal sides are equal.

Thus, ∠BAC=∠ACB=52o.

Therefore, yo=∠BAC=52o.

We know, by angle sum property, the sum of the angles of a triangle is 180∘ .

Then we have, 52o+(14x+6)o+52o=180o

⟹ 104o+14x+6o=180o

⟹ 110o+14x=180o

⟹ 14x=180o−110o

⟹ 14x=170o−110o=70o

⟹ x=1470o=5o.

Answer 2

Answer:

$\huge\sf\blue{AnSwEr}$

15° is the answer to your question.

$\mathtt\red{XxMeethiBacchixX ✨}$

Step-by-step explanation:

2x + 20° = 50°

2x = 50° – 20°

x = 30/2

x = 15°