ABC is an isosceles triangle having its height ad=64 cm and AB=AC=8cm and base BC=10cm find the area of triangle
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Answered by
24
we know that
.height is 64cm sq
base is 10 cm sq
we know that area of triangle is 1/2*base*height
therefore 1/2*64*10=320
ans 320
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.height is 64cm sq
base is 10 cm sq
we know that area of triangle is 1/2*base*height
therefore 1/2*64*10=320
ans 320
pls mark as brainliest
Answered by
7
since this is an isosceles triangle we could split and have a perpendicular bisector. since it is a bisector we know the bottom part of it would be 5 (half of 10) and the hypothenuse would be 13. this is a right triangle since the line we got was a perpendicular bisector.
using the pythagorean theorem we get height perpendicular bisector is 12.
13^2 - 5^2 = 144 = 12^2 so side is 12 and it would be the altitude to BC
now we find the area which is 1/2 ( b ) ( h ) we got the height/altitude which is 12 when base is 10
so area will be
1/2 ( 12 ) ( 10 ) = 60
using AB as the base the perpendicular which is the height would be solved by
2 A / b = h
120 / 13 would be the altitude to BC
using the pythagorean theorem we get height perpendicular bisector is 12.
13^2 - 5^2 = 144 = 12^2 so side is 12 and it would be the altitude to BC
now we find the area which is 1/2 ( b ) ( h ) we got the height/altitude which is 12 when base is 10
so area will be
1/2 ( 12 ) ( 10 ) = 60
using AB as the base the perpendicular which is the height would be solved by
2 A / b = h
120 / 13 would be the altitude to BC
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