∆ABC is an isosceles triangle. If CB = AC and AB² = 2AC², then prove that ∆ABC is a right triangle.
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Answer:
given - AB =AC
AB^2 =2AC^2
to proof - ABC is a right angle triangle
Step-by-step explanation:
In triangle ABC
AC=BC (given )
AB^2 = 2AC^2
AB^2 = AC^2 + AC^2
AB^2 = AC^2 + BC^2. ( AC = BC)
hence , proved ABC is a right angle triangle.
hope it is helpful
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