Math, asked by siddhant1658, 5 months ago

∆ABC is an isosceles triangle. If CB = AC and AB² = 2AC², then prove that ∆ABC is a right triangle. ​

Answers

Answered by virendersingh88
3

Answer:

given - AB =AC

AB^2 =2AC^2

to proof - ABC is a right angle triangle

Step-by-step explanation:

In triangle ABC

AC=BC (given )

AB^2 = 2AC^2

AB^2 = AC^2 + AC^2

AB^2 = AC^2 + BC^2. ( AC = BC)

hence , proved ABC is a right angle triangle.

hope it is helpful

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