Question

ABC is an isosceles triangle in which AB= AC= 17 cm and BC= 30 cm.
Angle AXB= Angle AXC =90°. Calculate the length of AX.

picture of the isosceles triangle right here
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Answer 1

Answer:

Given that

ABC is a isosceles triangle

AB=AC= 17 cm and BC = 30 cm

XC = BC /2

XC = 30 / 2

= 15 cm

Find the length of AX?

By Pythagoras theorem

Base ^2 + height ^ 2= hypotenuse^2

AX^2 + XC^2 = AC^2

AX^2 + 15^2 = 17^2

AX ^2 + 225 = 289

AX^2 = 289 - 225

AX ^2 = 64

AX^2 = 8 cm

Answer 2

Answer:

answer above

hope it helps