abc is an isosceles triangle in which ab=ac=7.6 and bc=9.5cm the perpendicular AD from A on side BC is 4cm find area of triangle abc and measure of perpendicular BE from B on side AC
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Area of triangleABC= 9.5*4*1/2
=9.5 * 2 =19cm^2
Also,
Area of triangle ABC = AC * BE
19 = 7.6 * BE * 1/2
19 = 3.8 * BE
19 / 3.8 = BE
5cm = BE
Here is your answer.
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