ABC is an isosceles triangle in which AB=AC and BC²=AB². Prove that ABC is a right angled triangle
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In △ABC,
By Pythagoras Theorem,
(AB)2=(AC)2+(BC)2. (1)
Since, △ABC is an isosceles triangle,
∴ AC=BC....(2)
∴ From (1) and (2),
(AB)2=2(AC)2 [henceproved]
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