Question

ABC is an isosceles triangle in which ab = AC and O is any point on BC perpendicular distance of a b and AC from point O and P and Q respectively and that of AC from point B is BD prove that op + ok equal to BD ​

Answer 1

Answer:

if ab= ac then angle b = angle c and o is the mid point of bc so angle aob and angle aoc are 90°

proof : In aob and aoc ,

ab = ac ( given)

angle aob = angle aoc ( each 90° )

angle abo = angle aco ( proof above )

aob congruent to aoc ( AAS )

ob + oc = bc ( CPCT)

BD is wrong worded it is BC and op+ ok is wrong worded it is ob+ oc .