Math, asked by premveersingh6580, 11 months ago

ABC is an isosceles triangle in which AB = AC. BE and CF are its two medians. Show that BE=CF.

Answers

Answered by nikitasingh79

To prove: BE = CF

Proof:

In ∆ABC, it is given that

AB = AC

[Angle opposite to equal sides are equal]

Again , AB = AC

½ AB = ½ AC

[∵ E & F the midpoints of AC and AB]

In ∆ BEC & CFB ,

CE = BF ( from eq 2)

∠B = ∠C (from eq1)

BC = CB (Common)

Therefore, By SAS congruence criterion , we obtain ∆ BEC ≅ CFB.

HOPE THIS ANSWER WILL HELP YOU…..

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Answered by tejashk259

Answer:

Given : ABC is an isosceles triangle in which AB = AC. BE and CF are its two medians.

To prove: BE = CF

Proof:

In ∆ABC, it is given that

AB = AC

∠B = ∠C ………….(1)

[Angle opposite to equal sides are equal]

Again , AB = AC

½ AB = ½ AC

BF = CE …………(2)

[∵ E & F the midpoints of AC and AB]

In ∆ BEC & CFB ,

CE = BF ( from eq 2)

∠B = ∠C (from eq1)

BC = CB (Common)

Therefore, By SAS congruence criterion , we obtain ∆ BEC ≅ CFB.

BE = CF (By CPCT)

HOPE THIS ANSWER WILL HELP YOU…..