Question

△ABC is an isosceles triangle in which AB=AC. BE and CF are the medians of △ABC. What will be the relation between the medians BE and CF

Answer 1

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Answer 2

Answer:

Here is the answer for the question

Step-by-step explanation:

ABC is an isosceles triangle (given)

AB = AC (given)

BE and CF are two medians (given)

 To prove: BE = CF

 In △CFB and △BEC  CE = BF (Since, AC = AB = AC/2 = AB/2 = CE = BF)

BC = BC (Common)

∠ECB = ∠FBC (Angle opposite to equal sides are equal)

By SAS theorem: △CFB ≅ △BEC

 So, BE = CF