ΔABC is an isosceles triangle in which AB=AC. d is the midpoint of base BC. prove that ΔABD≅ΔACD. if m ∠b=(3x-10)° and ∠m=70°, find the value of x.(Please answer it fast and also show the steps! Its really very urgent)
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its esy. CD=DB as D us the midpoint of BC
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Faiqa93:
The answer should be 20°
how?
That's what I don't understand so I have asked here
value or angle B or angle C is not given. so how it is possible to calculate the value of x
The angle b's value is 3x-10 and c is 70
so its 80/3
How??
in this triangle angle b is equal to angle c the put 70=3x-10 so x=80/3
Ok
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