ABC is an isosceles triangle in which AB=AC IF D and E are midpoints of AB and AC respectively, prove that B,C,D and E are concyclic. Please reply soon.
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DE parallel to BC (according to mid point)
ADE=ABC & AED=ACB
ADE=AED (i)
BDE=CED (ii)
adding (i)&(ii)
ADE+BDE=AED+CED=180
Hence, B,C,D,E are concyclic
ADE=ABC & AED=ACB
ADE=AED (i)
BDE=CED (ii)
adding (i)&(ii)
ADE+BDE=AED+CED=180
Hence, B,C,D,E are concyclic
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12
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