Question

ΔABC is an isosceles triangle in which AB=AC. Show that ∠B=∠C. (Hint : Draw AP⊥ BC) (Using RHS congruence rule)

Answer 1

Answer:

∠B = ∠C

Step-by-step explanation:

ΔABC is an isosceles triangle in which AB=AC

Let draw AP ⊥ BC

in Δ ABP

AB² = AP² +  BP²

in Δ ACP

AC² = AP² + CP²

AB = AC

Squaring both sides

=> AB² = AC²

so equating both equation

AP² +  BP² = AP² + CP²

=> BP² = CP²

=> BP = CP

in  Δ ABP  & Δ ACP

AB = AC  AP is commom

BP = CP

all sides are equal

=> Δ ABP  ≅ Δ ACP

=> ∠B = ∠C