Question

ABC is an isosceles triangle in which AB = BC and D is a point on the side AB.
If AD = BD, then CD is

Answer 1

Answer:

Step-by-step explanation:

We have,

  BC2=AC×CD and AB=AC

⇒ BC×BC=AC×CD and ∠B=∠C

⇒ ACBC​=BCCD​ and ∠B=∠C

⇒ CABC​=CBDC​ and ∠B=∠C

So, by SAS-criterion of similarity, we have

     △BCA∼△DCB

⇒  DCBC​=CBCA​=DBBA​

⇒  CBCA​=DBBA​

⇒ CABA​=CBDB​

⇒ 1=CBDB​           [∵   BA=CA]

⇒ DB=CB

⇒BD=BC        [Hence proved]

pls mark it as brainliest