Question

ABC is an isosceles triangle in which ab is equal to AC also the is a bit. Such that BD is equal to see this prove that ad bisects angle A and angle d

Answer 1

In the fig
AB=AC(given)
BD=DC(given)
AD=AD(common)
there for triangle ABD=Triangle ABC (SSS)
there for AD is the median (cpct)
so AD bisect angle A