Math, asked by agamveersandhu17, 1 day ago

ABC is an isosceles triangle in which AD ⊥ BC. Prove that ∆ BAD ≅ ∆ CAD

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Answered by rsaryant

2

Answer:

Step-by-step explanation:

In Δ BAD and Δ CAD

∠ ADB = ∠ ADC [Each 90°]

AB = AC [ABC is isosceles]

AD = AD [Common]

BY SAS congruency rule Δ BAD ≅ Δ CAD

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