ABC is an isosceles triangle in which AD BC Prove that BAD = CAD
wrong ans will be reported
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It is defective to use ∠ABD=∠ACD for proving this result.
△ABD and △ACD
AB=AC (given )
Then ∠ABD=∠ACD ( because AB=AC )
and ∠ADB=∠ADC=90( because AD⊥BC )
∴△ABD=△ACD
∠BAD=∠CAD
It is defective to use ∠ABD=∠ACD for proving this result
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