Question

ABC is an isosceles triangle in which altitude BE and CF are drawn two equal sides of AC and AB . show that these altitude are equal​

Answer 1

Answer:

Step-by-step explanation:

In △ABE and △ACF, we have  

∠AEB=∠AFC ∣ Since Each =90  

∠BAE=∠CAF ∣ Common

and AB=AC ∣ Given  

∴ By AAS criterion of congruence, we have  

△ABE≅△ACF

⇒BE=CF ∣ Since Corresponding parts of congruent triangles are equal.......................