Question

ABC is an isosceles triangle in which altitude BE and CF are drawn equal sides AC and AB respectively . Show that these altitudes are equal.

pls give only write explanation​

Answer 1

Step-by-step explanation:

In △ABE and △ACF,

we have ∠BEA=∠CFA (Each 90

0

)

∠A=∠A (Common angle)

AB=AC (Given)

∴△ABE≅△ACF (By SAS congruence criteria)

∴BF=CF [C.S.C.T]

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