Question

ABC is an isosceles triangle in which altitudes BE & CF are drawn
to sides Ac and AB respectively. Show that these altitudes are
equal
​

Answer 1

In △ABE and △ACF, we have

∠AEB=∠AFC ∣ Since Each =90°

∠BAE=∠CAF ∣ Common

and AB=AC ∣ Given

∴ By AAS criterion of congruence, we have

△ABE≅△ACF

⇒BE=CF ∣ Since Corresponding parts of congruent triangles are equal.

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