ABC is an isosceles triangle in which altitudes
BE and CF are drawn to equal sides AC and AB
respectively (see Fig. 7.31). Show that these
altitudes are equal.
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Step-by-step explanation:
in triangle BAE and triangle CAF
(i) angle A is common angle
(ii) AB=AC as ABC is isosceles triangle
(íii) angle CFA= angle BEA both are 90 degree
so therefore both triangles are congruent
now then, BE = CF
same side of congruent triangles
so PROVED
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