Math, asked by manisstrong, 5 hours ago

ABC is an isosceles triangle in which altitudes
BE and CF are drawn to equal sides AC and AB
respectively (see Fig. 7.31). Show that these
altitudes are equal.

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Answers

Answered by debanshubhattacharyy
1

Step-by-step explanation:

in triangle BAE and triangle CAF

(i) angle A is common angle

(ii) AB=AC as ABC is isosceles triangle

(íii) angle CFA= angle BEA both are 90 degree

so therefore both triangles are congruent

now then, BE = CF

same side of congruent triangles

so PROVED

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