Question

ABC is an isosceles triangle in which angle b is 90 and ac is 3 root 2

Answer 1

what is Yu want to find

Answer 2

ABC is an right isosceles triangle. then,
${ac}^{2} = {ab}^{2} + {bc}^{2} \\ {(3 \sqrt{2)} }^{2} = 2( {ab)}^{2} (beacause \: abc \: is \: isoseclus \: triangle.) \\ 18 = 2( {ab)}^{2} \\ 9 = {ab }^{2} \\ ab = 3 \\ ab = bc = 3$
plz mark as brainiest answer.