Math, asked by mahiway4056, 19 days ago

ABC is an isosceles triangle in which C = 90°. If AC = 5 cm, then what is the value of AB2 .

Answers

Answered by bagkakali
1

Answer:

here C=90°

as ABC is an isosceles, so , AC=BC=5cm

AB^2=AC^2+BC^2=5^2+5^2=25+25=50

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