Math, asked by Mahendrahdhdh, 10 months ago

ABC is an isosceles triangle inscribed in a circle if ab is equal to AC is equal to 12 root 5 cm and BC is equal to 24 cm find the radius of the circle

Answers

Answered by amitnrw
11

Radius of the circle = 15 cm if ABC nscribed in a circle  AB = AC = 12√5 cm & BC = 24 cm

Step-by-step explanation:

BC² = AB² + BC² - 2AB. BC Cos∠A

=> 24² = (12√5)² +  (12√5)² - 2 (12√5) (12√5)Cos∠A

=> 576 = 720 + 720  - 1440Cos∠A

=> Cos∠A =  864/1440

=>  Cos∠A =  3/5

=> ∠A =  Cos⁻¹(3/5)

Angle subtended by chord BC = A  = Cos⁻¹(3/5)

Angle subtended by BC at center = 2A

in Δ BOC  

BO = CO = R = Radius

BC = 24 cm

BC² = BO² + CO² - 2BO * CO Cos(2A)

=> 24² = R² + R² - 2R²Cos(2A)

=> 576 = 2R²(1 - Cos2A)

=> 288 = R² ( 1  -  (2Cos²A - 1))

=> 288 = R² (2 - 2Cos²A)

=> 144 = R² (1 - Cos²A)

=> 144 = R² ( 1  - (3/5)² )

=> 144 = R² (16/25)

=> R² = 25 * 9

=> R = 5 * 3

=> R = 15

radius of the circle = 15 cm

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