ABC is an isosceles triangle is which AB=AC=10cm and BC=12. PQRS is a rectangle inside the isosceles triangle. Given PQ=SR=y cm, PS=QR=2x. Prove that x = 6 -(3/4)y.
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ab = ac = 10
and
bc = 12
Also in rectangle
pq = rs = y
and qr = sp = x
Thus
in triangle abd
ad^2 = 10^2 + 6^2
= 100 + 36
ad = root 136
= 2 root 34
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