Question

∆ABC is an isosceles triangle.Its perimeter is 44 cm and base BC=12 cm AB=AC. An incircle intersects triangle at P,Q,R. AP=? AQ=?

Answer 1

Answer:

AP = AQ = 10 cm

Step-by-step explanation:

∆ABC is an isosceles triangle

AB = AC

Perimeter = 44 cm

Perimeter = AB + BC + AC

=> AB + 12 + AB = 44

=> 2AB = 32

=> AB = 16

AB = AC = 16 cm

AP = AQ Tangent

BP = BR Tangent

CQ = CR  Tangent

AP =  AB - BP = 16 - BR

AQ = AB - CQ = 16 - CR

Adding Both

AP + AQ = 32 - (BR + CR)

=> AP + AQ = 32 - BC

=> AP + AQ = 32 - 12

=> AP + AQ = 20

AP = AQ = 10

Answer 2

Answer:

AP = AP = 10 cm

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