Question

Abc is an isosceles triangle right angled At b.prove that ac²=2bc²

Answer 1

Answer:

Given:

Triangle ABC with angle B = 90 degrees

AB=BC

To Prove:

$AC^{2} = 2BC^2$

Proof:

$AB^2+BC^2=AC^2$............................(Pythagoras theorem)

Now, AB = BC (since abc is isosceles triangle)

thus, $AB^2=BC^2$

So, $BC^2 + BC^2 = AC^2$

Therefore,

ac²=2bc² proved

Hope it helps, please mark as brainliest :)