ABC is an isosceles triangle right angled at C. Prove that
![{ab}^{2} = {2ac}^{2} {ab}^{2} = {2ac}^{2}](https://tex.z-dn.net/?f=+%7Bab%7D%5E%7B2%7D++%3D+%7B2ac%7D%5E%7B2%7D+)
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Δ ABC is a right Δ and also isosceles triangle.,. To prove: Step 1: Proof: Here,. Hypotenuse = AB. Also, as it is given that, ΔABC is ...
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