Question

ABC is an isosceles triangle right angled at C. Prove that AB2=2AC2

Answer 1

here is your answer
Thanks for asking

Answer 2

Answer:

The required condition for right triangle ΔABC is AB²=AC²+BC².

From the question, we are given AB²=2AC².

We need to split 2AC² to solve question.

If we split 2AC², we have AB²=AC²+AC².

Then by the given condition AC=BC, we have AC²=BC².

Therefore, AB²=AC²+BC², therefore, ΔABC is a right triangle.

Step-by-step explanation: