Question

ABC is an isosceles triangle right angled at C. Prove that AB² = 2AC².

Answer 1

Your answer is on the attachment.

Hope it helps.

Answer 2

Hey there!

Given,
ABC is an isosceles triangle, right angled at C.

As C is the right angle, AB can't be one of the isosceles triangle.

So, AC = BC

By Pythagoras theorem,

$\mathbf{AB^{2} = AC ^{2} + BC ^{2} }$

Now, AC = BC

AB² = AC² + AC²

AB² = 2AC²

If you want a proof without using Pythagoras theorem , Let's prove with Similarity .

Check the attachment for that!


Hope helped!