Question

ABC is an isosceles triangle, right angled at C. Prove that
AB(square) = 2AC(square).

Answer 1

Step-by-step explanation:

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Answer 2

$\huge\purple{\mathbb{ANSWER}}$

In ∆ABC :—

AC=BC.........................①

∠ C=90°

AB² = AC² + BC²............(By Pythagoras Theorem)

From ①:—

AB² = 2AC²

Hence, Proved.