. ABC is an isosceles triangle right-angled at c. prove that AB? = 2AC2.
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given that triangle ABC
and right angled at C
AB=2AC2
in isosceles triangle two sides are equal
so, the sides are AB, BC, AC
angle A = angle B ( it has one angle is 90 and remaining angles are equal because it is a isosceles triangle)
Opposite sides of angleA and angleB are equal
that are AB=BC then the answer is 2AC2
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