Question

ABC is an isosceles triangle.right angled at C .prove that AB^2=AC^2

Answer 1

we know that in isocles triangl two sides are equal
to prove;ab^2=ac^2
bc=ac .....1
using pythagrous theroem
ab^2=ac^2+bc^2 
from 1   bc=ac
∴ab²=ac²+bc²
AB²=AC²+AC²
AB²=2AC²