abc is an isosceles triangle right angled at c. prove that ab=2ac
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Answered by
6
Given :ABC is an isosceles right angle triangle at C
AC= BC
To prove : AB = 2AC
Proof : using Pythagoras theorem
AB² =AC²+BC²
AB² = AC² +AC²
AB² = 2 AC²
Hope this helps ^-^!!
AC= BC
To prove : AB = 2AC
Proof : using Pythagoras theorem
AB² =AC²+BC²
AB² = AC² +AC²
AB² = 2 AC²
Hope this helps ^-^!!
nakulmaheshwari:
thanks
According to you if we further up,
AB=underroot 2 * AC
In this case, AB can never be equal to 2AC it's impossible if it is isosceles triangle.
yes ,ur correct
we prooved the same
Answered by
5
given ABC is a right angled triangle
<c=90 and BC=AC(isosceles triangle)
hypotenuse square = sum of squares of the other two angles
AB^2= AC^2+BC^2
=AC^2+AC^2
=2AC^2
AB^2=2AC^2
AB=root 2*AC
<c=90 and BC=AC(isosceles triangle)
hypotenuse square = sum of squares of the other two angles
AB^2= AC^2+BC^2
=AC^2+AC^2
=2AC^2
AB^2=2AC^2
AB=root 2*AC
thanks
You're right but you've failed to prove AB=2AC however it can't be possible. Do you agree with that?
AB can never be equal to that may be the user didn't know how to make square in question!!
And u r right
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