Math, asked by rishukumar7th, 1 year ago

ABC is an isosceles triangle; RIGHT ANGLED at C prove that AB ^2 =2AC^2

Answers

Answered by creamiepie
5
<b>INTRODUCTION:-</b> ABC is an isosceles triangle . where \angle{C} = 90° . AC = BC

<b>TO PROVE:-</b>
 {AB}^{2}  = 2 {AC}^{2}

<b>PROOF:-</b> Applying Pythagoras theorem

 {AB}^{2}  =  {AC}^{2}  +  {BC}^{2}(AC = BC)\\  \\  =  > {AB}^{2} = {AC}^{2} + {AC}^{2} \\ \\ => {AB}^{2}= 2{AC}^{2}
Answered by Anonymous
5

ur answer is attached....

hope it's helpful for u....

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