Question

∆ABC is an isosceles triangle, right angled at C, with AC = 2 cm, then

find the length of hypotenuse.​

Answer 1

Answer:

AB = 2√2 cm ( hypotenuse)

Step-by-step explanation:

AC2 + BC2 = AB2

2 square + 2 square ( isosceles triangle have both sides same length) = AB 2

4 cm +4 cm = AB2

8 cm = AB2

AB = 2√2 cm

Answer 2

Answer :

Hypotenuse = 2√2 cm

Step-by-step explanation:

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Given,

ΔABC is an isosceles triangle

∠C = 90°

Since the triangle is an isosceles triangle,

the two sides other than hypotenuse are equal.

 AC = BC = 2 cm

Hypotenuse is the longest side of the right angled triangle.

hypotenuse = AB

we have to find the length of the hypotenuse i.e., AB = ?

By Pythagoras theorem,

AB² = AC² + BC²

AB² = (2 cm)² + (2 cm)²

AB² = 4 cm² + 4 cm²

AB² = 8 cm²

AB = √(8 cm²)

AB = √8 cm

AB = √(4×2) cm

AB = 2√2 cm

Therefore,

the length of the hypotenuse = 2√2 cm