Question

ABC is an isosceles triangle right angled at C with AC = 4cm. Then half the length of AB will be​

Answer 1

Answer:

\DeltaABC is an isosceles triangle

Right-angled at C [\angle C = 90\degree]

AC = 4cm

AB = ?

\DeltaABC = isosceles \Rightarrow AC = BC = 4 cm

AB = \sqrt{AC^2 + BC^2}

AB = \sqrt{4^2 + 4^2}

AB = \sqrt{16+ 16}

AB = \sqrt{32}

AB = 4\sqrt{2}

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