ABC is an isosceles triangle rights angled at C. Prove that AB2 =2AC2.
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Answer:
since the triangle is isosceles and right angled at C
AC = BC
now
by Pythagoras theorem
Hypotenuse² = base²+perpendicular ²
AB² = BC² + AC²
AB² = AC² + AC² ( AC = BC)
AB² = 2AC²
Step-by-step explanation:
hence proved!!!!
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