∆Abc is an isosceles triangle such that ab=ac.d is a point on sideab such that bc=cd.given angle bac=28°.find the value of angle dca.
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Answered by
1
Answer:
76°
Step-by-step explanation:
In ∆ABC, AB= AC
=> Angle C = Angle B
Sum of all interior angles of a triangle = 180°
=> angle A + angle B + angle C = 180°
= 28° + 2 angle B = 180°
2 angle B = 180° - 28° = 152°
=> angle B = 152/2 = 76° = angle C
Given that D is a point on AB
=> angle DCA = angle C = 76°
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Answered by
1
Answer:
Step-by-step explanation:
In ∆ABC, AB= AC
=> Angle C = Angle B [given ]
Sum of all interior angles of a triangle = 180°
=> angle A + angle B + angle C = 180°
= 28° + 2 angle B = 180°
2 angle B = 180° - 28° = 152°
=> angle B = 152/2 = 76° = angle C [angle C = angle D]
Given that D is a point on AB
=> angle DCA = angle C = 76°
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