Question

ABC is an isosceles triangle. The area of the triangle is 100cm^2
what is the length of AB?
Angle ABC=ACB=45
Angle CAB=90

Answer 1

Answer:

$10\sqrt2$ cm

Step-by-step explanation:

As it is an isosceles triangle, let the length of the two sides (AB and BC) be equal to x cm.

As one of the angles of the triangle (angle CAB) is 90 degrees, it is a right-angled triangle.

For a right-angled triangle: $Area=\frac12*b*h$

In this case, base and height are both x, as it is an isosceles triangle.

So, $100 = \frac12*x*x$

or $200 = x^2$

Hence, the value of x is $\sqrt{200}=10\sqrt2$

Hence, AB = $\sqrt{200}=10\sqrt2$ cm

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