Math, asked by ttahersayed, 1 month ago

∆ABC is an isosceles triangle. The length of base BC is 16. AB = AC =9, then length of the altitude AD =

A √17

B √14

C √337

D √65​

Answers

Answered by cashcashjames
3

Answer:

17

Step-by-step explanation:

Since altitude AD form a 90° angle, we have

AC=9, CD=8 AD=?

By Pythagoras theorem we have,

AC² = AD² + CD²

9² = AD² + 8²

AD = √9² + 8²

AD = 9 + 8

Therefore AD = 17

Answered by amitnrw
12

Given : ∆ABC is an isosceles triangle.

The length of base BC is 16.

AB = AC =9,

To Find : length of the altitude AD  

Solution:

AB = AC =9

BC is 16.

altitude AD   in isosceles triangle will divided Base

Hence BD = CD = BC/2 =  16/2 = 8 cm

in  ΔABD using Pythagorean theorem :

AB² = AD²  + BD²

=> 9²  = AD²  + 8²

=> 81 = AD²  + 64

=> AD² = 17

=> AD = √17

length of the altitude AD = √17  

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