∆ABC is an isosceles triangle. The length of base BC is 16. AB = AC =9, then length of the altitude AD =
A √17
B √14
C √337
D √65
Answers
Answer:
17
Step-by-step explanation:
Since altitude AD form a 90° angle, we have
AC=9, CD=8 AD=?
By Pythagoras theorem we have,
AC² = AD² + CD²
9² = AD² + 8²
AD = √9² + 8²
AD = 9 + 8
Therefore AD = 17
Given : ∆ABC is an isosceles triangle.
The length of base BC is 16.
AB = AC =9,
To Find : length of the altitude AD
Solution:
AB = AC =9
BC is 16.
altitude AD in isosceles triangle will divided Base
Hence BD = CD = BC/2 = 16/2 = 8 cm
in ΔABD using Pythagorean theorem :
AB² = AD² + BD²
=> 9² = AD² + 8²
=> 81 = AD² + 64
=> AD² = 17
=> AD = √17
length of the altitude AD = √17
Learn More:
the base of a right angled triangle exceeds the corresponding height ...
brainly.in/question/14793579
In the given figure, altitude BD is drawn to the hypotenuse AC of a ...
brainly.in/question/12282134
The smallest angle in a 3-4-5 right-angled triangle is very closeto 37 ...
brainly.in/question/16309602