Question

ABC is an isosceles triangle where AB =AC =12 cm and BC=8 cms Find the altitude on the BC and hence calculate the area​

Answer 1

Step-by-step explanation:

here is your answer bro

hope this helps you

Answer 2

Step-by-step explanation:

The altitude of an isosceles triangle is also the median of the base of triangle.

So , let the mid point of BC be P.

Then , BP = PC

AB square = BP square + AP square

12^2 = 4^2(8/2=4) + AP^2

144 = 16 + AP^2

AP = √144-16

AP = 8√2 cm

Now , Area = 1/2 * base * height

= 1/2 * 8 * 8√2

=32√2 cm square