Question

ABC is an isosceles triangle where AB=AC where the side CB is extended to x towards B.angle A = 80 degree and angle ABX=130 degree. find angle B and angle C​

Answer 1

Answer:

AB=AC, ∠ACD=130

∠ACD+∠ACB=180 (Linear pair)

130+∠ACB=180

∠ACB=50

∘

Now, In △ABC,

∠ABC=∠ACB=50 (Isosceles triangle property)

Sum of angles = 180

∠ABC+∠ACB+∠BAC=180

50+50+∠BAC=180

∠BAC=80

∘

Answer 2

Step-by-step explanation:

Given: AB=AC, ∠ACD=130

∠ACD+∠ACB=180 (Linear pair)

130+∠ACB=180

∠ACB=50

∘

Now, In △ABC,

∠ABC=∠ACB=50 (Isosceles triangle property)

Sum of angles = 180

∠ABC+∠ACB+∠BAC=180

50+50+∠BAC=180

∠BAC=80

∘