Question

ABC is an isosceles triangle with a b equal to AC and BD and ce its two medians show that BD equal to ce

Answer 1

AE=EB (EC MEDIAN)
similarly
AD=DC(BD MEDIAN)
AB=AC(GIVEN)
1/2AB=1/2AC
EB=DC(EC IS MEDIAN AND AD IS MEDIAN)
IN ∆EBC AND ∆DBC
BC=BC(COMMON)
EB=DC(PROVED)
ANGLE B =ANGLE C
∆EBC~∆BDC(SAS RULE)
BD=CE