Question

ABC is an isosceles triangle with AB=AC=10cm and BC=6cm. Find the altitude on BC and also calculate its area.​

Answer 1

hey mate,

here's your answer

a=10

b=10

c=6

s=a+b+c/2

s=10+10+6/2

s=26/2

s=13cm

area=√s(s-a)(s-b)(s-c)

area=√13(13-10)(13-10)(13-6)

area=√13×3×3+×7

area=√810

area=28.61cm^2

for altitude,

area= 1/2× base × height

28.61=1/2×6×height(altitude)

28.61=3×altitude

altitude=28.61÷3

altitude=9.53cm(approximately)

Answer 2

Step-by-step explanation:

a=10

b=10

c=6

s=a+b+c/2

s=10+10+6/2

s=13cm

area=✓s (s-a)(s-b)(s-c))

=✓13(13-10)(13-10)(13-6)

=✓13×3×3×7

=8✓10

=28.61 cm^2

for altitude