Math, asked by harshilsaijayabalan, 9 months ago

ABC is an isosceles triangle with AB = AC = 2008 cn
cm. ADC is drawn as an equilateral triangle on AC outside
AAIC. AD is parallel to BC. The bisector of D meets AB in E. say. Then BE is equal to

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Answered by dharu2008

0

Answer:

sorry.....................................

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